Question

Помогите пожалуйста. Алгебра 9 класс!​

Answer 1

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Answer 2

$p(\frac{1}{b})=(\frac{1}{b}-\frac{1}{\frac{1}{b}})(-\frac{1}{b}+\frac{1}{\frac{1}{b}})=(\frac{1}{b}-b)(b-\frac{1}{b})\\\\p(b)=(b-\frac{1}{b})(-b+\frac{1}{b})=(\frac{1}{b}-b)(b-\frac{1}{b})\\\\\frac{p(b)}{p(\frac{1}{b})}=\frac{(\frac{1}{b}-b)(b-\frac{1}{b})}{(\frac{1}{b}-b)(b-\frac{1}{b}}=1$