Question

Помогите срочно прошу

Answer 1

Объяснение:

(m^(1/3) -m^(1/6) •n^(1/6))/m^(1/3) ÷(m^(1/3) -2m^(1/6) •n^(1/6) +n^(1/3))/(m^(1/6) •n^(1/6))=(m^(1/6) •(m^(1/6) -n^(1/6))/m^(1/3) •(m^(1/6) •n^(1/6))/(m^(1/6) -n^(1/6))^2=(m^(1/6) •n^(1/6))/(m^(1/6) •(m^(1/6) -n^(1/6))=(n^(1/6))/(m^(1/6) -n^(1/6))=(^6√n)/(^6√m -(^6√n))