Question

Номер 6, 20 баллов!!!!!

Answer 1

$3\frac{3}{7}\, x^5y^6\cdot (-2\frac{1}{3}\, x^5y)^2=\frac{24}{7}\, x^5y^6\cdot (\frac{7}{3})^2\, x^{10}y^2=\frac{24\cdot 7}{9}x^{15}\, y^8=18\frac{2}{3}\, x^{15}\, y^8\\\\\\(a^{n+1})^2:a^{2n}=a^{2n+2}:a^{2n}=a^{2n+2-2n}=a^2$