Question

Записать уравнения реакции взаимодействия пропионовой кислоты с :

1)NaOH

2)Zn

3)CaO

4)K2CO3

5)CH3OH

6)C2H5OH

Answer 1

C2H5COOH + NaOH = C2H5COONa + H2O

2C2H5COOH + Zn = (C2H5COO)2Zn + H2

2C2H5COOH + CaO = (C2H5COO)2Ca + H2O

2C2H5COOH + K2CO3 = 2C2H5COOK + H2O + CO2

C2H5COOH + CH3OH = C2H5COOCH3 + H2O

C2H5COOH + C2H5OH = C2H5COOC2H5 + H2O