Question

Неравенство с иксами в степенях?

Answer 1

Ответ:-1·2=-2............................

Answer 2

$25^{x} -9*4^{x-1}*5^{x}+5*4^{2x-1}>0\\\\5^{2x}-9*\frac{1}{4}*4^{x}*5^{x}+5*\frac{1}{4}*4^{2x}>0|*4\\\\4*5^{2x}-9*4^{x}*5^{x}+5*4^{2x}>0|:4^{2x}>0\\\\4*(\frac{5}{4})^{2x}-9*(\frac{5}{4})^{x}+5>0\\\\(\frac{5}{4})^{x}=m,m>0$

$4m^{2}-9m+5>0\\\\4(m-1)(m-\frac{5}{4})>0\\\\(m-1)(m-\frac{5}{4})>0\\\\1)m<1\\\\(\frac{5}{4})^{x}<1\\\\(\frac{5}{4})^{x}<(\frac{5}{4})^{o}\\\\x<0\\\\2)m>\frac{5}{4}\\\\(\frac{5}{4})^{x}>\frac{5}{4}\\\\x>1\\\\x\in(-\infty;0)\cup(1;+\infty)\\\\2*(-1)=-2\\\\Otvet:\boxed{-2}$