Question

(1-log8(24))(1-log3(24))=

Answer 1

$(1-log_824)(1-log_324)=(1-\frac{1}{3}log_2(2^3\cdot 3))(1-log_3(2^3\cdot 3)=\\\\=(1-1-\frac{1}{3}log_23)(1-3log_32-1)=-\frac{1}{3}log_23-\frac{3}{log_23}=-\frac{log_2^23+9}{log_23}$