Question

Решить уровнения только 2,4​

Answer 1

$2)\;\frac y2-\frac y8=\frac y4-1\\\\\frac y2-\frac y8-\frac y4=-1\\\\\frac{4y}8-\frac y8-\frac{2y}8=-1\\\\\frac y8=-1\\\\y=-8$

$4)\;\frac x3-\frac{2x}9=\frac x6+\frac12\\\\\frac x3-\frac{2x}9-\frac x6=\frac12\\\\\frac{6x}{18}-\frac{4x}{18}-\frac{3x}{18}=\frac12\\\\-\frac y{18}=\frac12\\\\y=\frac12:\left(-\frac1{18}\right)\\\\y=\frac12\cdot\left(-18\right)=-9$