Question

помогите пожалуйста

$x + \frac{1}{9} \times x = 1 \frac{2}{3}$
​

Answer 1

$\tt\displaystyle x+\frac{1}{9}x=1\frac{2}{3}\\\\\\1\frac{1}{9}x=\frac{1*3+2}{3}\\\\\\\frac{1*9+1}{9}x=\frac{5}{3}\\\\\\\frac{10}{9}x=\frac{5}{3}\\\\\\x=\frac{5}{3}:\frac{10}{9}\\\\\\x=\frac{5}{3}*\frac{9}{10}\\\\\\x=\frac{3}{2}\\\\\\x=1,5$

Ответ: 1,5

Answer 2

Решить уравнение.

$x + \dfrac{1}{9}\cdot x = 1\dfrac{2}{3};\\\\1\cdot x + \dfrac{1}{9}\cdot x = \dfrac{1*3+2}{3};\\\\\dfrac{9}{9}\cdot x + \dfrac{1}{9}\cdot x = \dfrac{5}{3};\\\\\left(\dfrac{9}{9} + \dfrac{1}{9}\right)\cdot x = \dfrac{5}{3};\\\\\dfrac{10}{9}\cdot x = \dfrac{5}{3};\\\\x = \dfrac{5}{3}:\dfrac{10}{9};\\\\x = \dfrac{5}{3}\cdot\dfrac{9}{10};\\\\x = \dfrac{3}{2};\\\\x = 1\dfrac{1}{2}.$

Ответ: $\bf x = 1\dfrac{1}{2}.$