Question

lim 2x^2+5x+7\3x^4-2x^2+x

Answer 1

$\lim_{x\rightarrow \infty }\frac{2x^2+5x+7}{3x^4-2x^2+x}=\lim_{x\rightarrow \infty }\frac{\frac{2}{x^2}+\frac{5}{x^3}+\frac{7}{x^4}}{3-\frac{2}{x^2}+\frac{1}{x^3}}=\frac{0}{3}=0$