Question

Срочно нужно решить хоть одну пж даю 100 баллов​

Answer 1

$1)\; \; 3^{2-3\sqrt3}\cdot 27^{\sqrt3}= 3^{2-3\sqrt3}\cdot (3^3)^{\sqrt3}= 3^{2-3\sqrt3}\cdot 3^{3\sqrt3}=3^{2-3\sqrt3-3\sqrt3}=\\\\=3^2=9\\\\\\2)\; \; a^{\sqrt2}\cdot a^{1-\sqrt2}=a^{\sqrt2+1-\sqrt2}=a^1=a\\\\\\3)\; \; 0,3^{x^3-x^2+x-1}=1\\\\ 0,3^{x^3-x^2+x-1}=0,3^0\\\\x^3-x^2+x-1=0\\\\x^2(x-1)+(x-1)=0\\\\(x-1)(\underbrace {x^2+1}_{>0})=0\; \; \; \Rightarrow \quad x-1=0\; ,\; \boxed{x=1}$

$4)\; \; \left \{ {{y=2x-1} \atop {7x-y=0}} \right.\; \; \left \{ {{y=2x-1} \atop {7x-(2x-1)=0}} \right.\; \; \left \{ {{y=2x-1} \atop {5x=-1}} \right.\; \; \left \{ {{y=-1,4} \atop {x=-0,2}} \right.$