Question

Решите уравнения:
$1) (x+4)^{5} = 0\\2) x^{11} = -1\\3) x^{10} = 1\\4) x^{7} + 1 = 0\\5) x^{10} + 1 = 0\\6) x^{7} = 3^{28}\\7) x^{6} = 2^{12}$

Answer 1

$1) {(x + 4)}^{5} = 0 \\ x + 4 = 0 \\ x = - 4 \\ 2) {x}^{11} = - 1 \\ x = - 1 \\ 3) {x}^{10} = 1 \\ x1 = - 1 \\ x2 = 1 \\ 4) {x}^{7} + 1 = 0 \\ {x}^{7} = - 1 \\ x = - 1 \\ 5){x}^{10} + 1 = 0 \\ {x}^{10} = - 1$

х∉R

$6) {x}^{7} = {3}^{28} \\ x = \sqrt[7]{ {3}^{28} } \\ x = {3}^{4} \\ x = 81 \\ 7) {x}^{6} = {3}^{12} \\ x = \sqrt[6]{ {3}^{12} } \\ x1 = 9 \\ x2 = - 9$