Question

$\sqrt{27 } + 5 \sqrt{48} - 2 \sqrt{108}$
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Answer 1

Ответ:

$\sqrt{27} +5\sqrt{48}-2\sqrt{108}=\sqrt{9*3} +5\sqrt{16*3}-2\sqrt{36*3}=\\=3*\sqrt{3} +5*4*\sqrt{3}-2*6*\sqrt{3}=(3+20-12)*\sqrt{3} =11*\sqrt{3}$