Question

помогите 4.5.6 пожалуйста

Answer 1

ОДЗ: 2x+3 ≠ 0, x ≠ -3\2

$\frac{x+1.5}{2(x+1.5)} = 0.5\\\frac{1}{2} = 0.5 \\0.5=0.5$

x∈(-∞;-1,5)∪(-1,5; +∞)

5)

$\frac{(x^{3} -27) }{x-3} =27\\\frac{(x-3)(x^{2} +3x +9) }{x-3} =27\\\\ x^{2} +3x+9=27\\ x^{2} +3x-18 = 0\\ x1=-6 \\x2 = 3 \\x1+x2=-6+3=-3$

6) $\frac{x(x-1)}{x^{2}-3x } =0 \\\frac{x(x-1)}{x(x-3)} = 0\\\frac{x-1}{x-3} =0\\x-1=0 \\x=1$