Question

$x^{4} =2$ помогите

Answer 1

Ответ:

$x^{4} =2\\x^{4}-2=0\\(x^{2}-\sqrt{2})(x^{2}+\sqrt{2})=0\\1)x^{2}-\sqrt{2}=0\\x^{2}=\sqrt{2}\\x=+-\sqrt{\sqrt{2}}\\2)x^{2}+\sqrt{2}=0\\x^{2}=-\sqrt{2}\\x\neq N,Z,Q$

Answer 2

Объяснение:

$x^4=2\\x=\pm\sqrt[4]{2} \\x_1=\sqrt[4]{2} , x_2=-\sqrt[4]{2}$