Question

Решите систему уравнений.
Номер 4

Answer 1

$\left \{ {{\frac{3x-2}{4y+3}=\frac{4}{15}} \atop {\frac{5x-y}{3y-2}=1 }} \right. \\\\\\\left \{ {{15*(3x-2)=4*(4y+3)} \atop {5x-y=3y-2}} \right.\\\\\\\left \{ {{45x-30-16y-12=0} \atop {5x-4y=-2}} \right. \\\\\\\left \{ {{45x-16y=42} \atop {5x-4y=-2|*(-4)}} \right.$

$+\left \{ {{45x-16y=42} \atop {-20x+16y=8}} \right.\\ -------\\25x=50\\\\x=2\\\\4y=5x+2=5*2+2=12\\\\y=3\\\\Otvet:\boxed{(2;3)}$