Question

Срочно плиз, даю 50 баллов

Answer 1

$1)\; \; 16x(2-x)+(4x-5)^2=0\\\\32x-16x^2+16x^2-40x+25=0\\\\8x=25\; \; ,\; \; x=3,125\\\\2)\; \; 9x^2-1=(3x-2)^2\\\\9x^2-1=9x^2-12x+4\\\\12x=5\; \; ,\; \; x=\frac{5}{12}\\\\3)\; \; 4y^3-3y^2-4y+3=0\\\\y^2(4y-3)-(4y-3)=0\; \; ,\; \; \; (4y-3)(y-1)(y+1)=0\\\\y_1=0,75\; \; ,\; \; y_2=-1\; \; ,\; \; y_3=1$

$4)\; \; 3(2-y)^2+4(y-5)^2=3(4-4y+y^2)+4(y^2-10y+25)=\\\\=7y^2-52y+112\\\\5)\; \; 5(3-5x)^2-5(3x-7)(3x+7)=5(9-30x+25x^2)-5(9x^2-49)=\\\\=80x^2-150x+290$