Question

Tg(4x-п/4)=√3
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Answer 1

$tg(4x-\frac{\pi}{4})=\sqrt3\\\\4x-\frac{\pi}{4}=\frac{\pi}{3}+\pi n\; ,\; n\in Z\\\\4x=\frac{7\pi}{12}+\pi n\; ,\; n\in Z\\\\x=\frac{7\pi }{48}+\frac{\pi n}{4}\; ,\; n\in Z$