Question

Помогите 3 и 4
100 баллов

Answer 1

№ 3) $\frac{21*21^7}{21^6} - \frac{3^5*6^5}{18^3} =$ $117$

1. $\frac{21*21^7}{21^6}=\frac{21^1^+^7}{21^6} = \frac{21^8}{21^6} = 21^8^-^6=21^2=441$

2. $\frac{3^5-6^5}{18^3}= \frac{(3*6)^5}{18^3}= \frac{18^5}{18^3}=18^5^-^3=18^2=324$

3. $441-324=117$

№ 4) $\frac{(x^7)^3*(x^3)^9:(x^4)^6}{x^2^3}= 4112$

$\frac{x^7^*^3*x^3^*^9:x^4^*^6}{x^2^3}=4112$

$\frac{x^2^1*x^2^7:x^2^4}{x^2^3} =4112$

$\frac{x^2^1^+^2^7^-^2^4}{x^2^3} =4112$

$\frac{x^2^4}{x^2^3} =4112$

$x^2^4^-^2^3=4112$

$x^1=4112$

$x=4112$

Answer 2

Ответ:

$3)117$

$4)x = 4112$

Объяснение:

$1) \frac{21 \times {21}^{7} }{ {21}^{6} } - \frac{ {3}^{5} \times {6}^{5} }{ {18}^{3} } = \frac{ {21}^{8} }{ {21}^{6} } - \frac{ {3}^{5} \times {6}^{5} }{ {6}^{3} \times {3}^{3} } = {21}^{2} - {3}^{2} \times {6}^{2} = {(7 \times 3)}^{2} - {3}^{2} \times {6}^{2} = {7}^{2} \times {3}^{2} - {3}^{2} \times {6}^{2} = {3}^{2} ( {7}^{2} - {6}^{2} ) = 9(49 - 36) = 9 \times 13 = 117$

$4) \frac{ {( {x}^{7} )}^{3} \times {( {x}^{3} )}^{9} \div {( {x}^{4} )}^{6} }{ {x}^{23} } = 4112 \\ \frac{ {x}^{21} \times {x}^{27} \div {x}^{24} }{ {x}^{23} } = 4112 \\ \frac{ {x}^{21 + 27 - 24} }{ {x}^{23} } = 4112 \\ \frac{ {x}^{24} }{ {x}^{23} } = 4112 \\ x = 4112$

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