Question

Решите
 $7(2x-1)-6(11-x)=3(x+4)$
и
$(x-3)(x-4)=x^2+2x-11$

Answer 1

$7(2x-1)-6(11-x)=3(x+4) \ 14x-7-66+6x=3x+12 \ 17x=85 \ x=5$

$(x-3)(x-4)=x^2+2x-11 \ x^2-3x-4x+12=x^2+2x-11 \ -9x=-23 \ x= cfrac{23}{9}$

Answer 2

14x-7-66+6x=3x+12
20x-73=3x+12
17x=85
x=5
x^2+12-7x=x^2+2x-11
9x=23
x=23/9