Question

Найти массовые доли веществ в соединении Ca(OH)2, Al2O3

Answer 1

Ответ:

Объяснение:

Mr(Ca(OH)2 = 40 + 16*2 + 1*2 = 74

W(Ca) = Ar(Ca) *n / Mr(Ca(OH)2)  *100% = 40*1 / 74  *100% = 54%

W(O) = Ar(O) *n / Mr(Ca(OH)2)  *100% = 16*2 / 74  *100% = 43%

W(H) = Ar(H) *n / Mr(Ca(OH)2)  *100% = 1*2 / 74  *100% = 3%

Mr(Al2O3) = 27*2 + 16*3 = 102

W(Al) = Ar(Al) *n / Mr(Al2O3)  *100% = 27*2 / 102  *100% = 53%

W(O) = Ar(O) *n / Mr(Al2O3)  *100% = 16*3 / 102  *100% =47%