Question

Помогите, пожалуйста

Answer 1

BPD~BCP  

BP/BC=BD/BP => BP^2 =BC*BD  

BD =AB*cosB  

S =AB*BC*sinB/2 => AB*BC =2S/sinB  

BP^2 =BC*BD =AB*BC*cosB =2S*ctgB  

Аналогично BQ^2 =2S*ctgB  

BP*BQ =2S*ctgB  

cosB=4/5 => ctgB=4/3  

BP*BQ =2*6*4/3 =16