Question

разложить на множители​

Answer 1

Ответ:

1) (3a-4)(3a+4)

2) 2(x²+2)-x⁴(2+x²) = (2-x⁴)(x²+2) = - (x⁴-2)(x²+2)

3) (5a-1)²

4) (2m)³-3³ = (2m-3)((2m)²+2m*3+ 3²) = (2m-3)(4m²+6m+9)

5) (6y - 7 - (9y + 4))*(6y - 7 + ((9y+4)) = (6y-7-9y-4)(6y-7+9y+4) = (-3y-11)(15y-3) = 3(5y-1)(-3y-11)