Question

решите уравнения:1)3(x+3)-15=3x+6-4x


2)7|x-4|=175
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Answer 1

1)

$3(x + 3) - 15 = 3x + 6 - 4x \ 3x + 9 - 15 = 3x + 6 - 4x \ 3x - 3x + 4x = 6 + 15 - 9 \ 4x = 12 \ x = frac{12}{4} \ x = 3$

Ответ: 3

2)

$7 |x - 4| = 175 \ |x - 4| = 25 \ \ x - 4 = 25 \ x = 25 + 4 \ x = 29 \ \ x - 4 = - 25 \ x = - 25 + 4 \ x = - 21$

Ответ: 29; -21

Answer 2

1)3(х+3)-15=3х+6-4х

3х+9-15=3х+6-4х

3х-3х+4х=6-9+15

4х=12

х=12:4

х=3

Ответ:х=3

2)7|х-4|=175

|х-4|=175:7

|х-4|=25

х-4≥0....................х-4<0

х-4=25...................-(х-4)=25

х=25+4....................-х+4=25

х=29......................-х=25-4

...............................-х=21

...............................х=-21

Ответ: х=29, х=-21