Question

$1) sqrt{2x + 1} = 1 \ 2) sqrt{x + 2} = x$
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Answer 1

Ответ:

$x_1 = - 1 \ x_2 = 2$

Объяснение:

$1) sqrt{2x + 1} = 1 \ 2x + 1 = 1 \ 2x = 0 \ x = 0 \ \ 2) : sqrt{x + 2} = \ x + 2= {x}^{2} \ x + 2 - {x}^{2} = 0 \ - {x}^{2} + x + 2 = 0 \ {x}^{2} - x - 2 = 0 \ {x}^{2} + x - 2x - 2 =0 \ x(x + 1) - 2(x + 1) = 0 \ (x + 1)(x - 2) = 0 \ x + 1 = 0 \ x_1 = - 1 \ x - 2 = 0 \ x_2 = 2$