Question

1/3х-4/9>х(х-1)
Помгите​

Answer 1

$frac{1}{3} x-frac{4}{9} >x^{2} -x\frac{1}{3} x-frac{4}{9} -x^{2} +x>0\frac{4}{3}x-frac{4}{9} -x^{2} +x>0\12x-4-9x^{2} >0\-(9x^{2} -12x+4)>0\-(3x-2)^{2} >0\(3x-2)^{2} <0$

$x$∈∅

Answer 2

$frac{1}{3} - frac{4}{9} > x(x - 1)$

$frac{1}{3} - frac{4}{9} > 2x - 1$

$- frac {1}{9} > 2x - 1$

$2x = frac{10}{9}$

$x = - frac{8}{9}$

удачи)