Question

Помогите решить, пожалуйста, 2 номера

Answer 1

$6 {x}^{4} {y}^{ - 3 } = 6 times {2}^{4} times {1}^{ - 3} = 6 times 16 times 1 = 96$

${3}^{2} times {x}^{2} times {y}^{ - 4} = 9 times {2}^{2} times {1}^{ - 4} = 9 times 4 = 36$