Question

геометрическая прогрессия помогите пжлст​

Answer 1

$b_{1} = dfrac{16}{27}; b_{2} = dfrac{16}{9}$

$q = dfrac{b_{2}}{b_{1}} = dfrac{dfrac{16}{9} }{dfrac{16}{27} } = 3$

$b_{8} = b_{1}q^{7} = dfrac{16}{27} cdot 3^{7} = 16 cdot 3^{-3} cdot 3^{7} = 16 cdot 3^{4} = 16 cdot 81 =1296$

Ответ: 1296.