Question

Ради бога помогите пожалуйста

Answer 1

$1); ; (4a^2b^4)^3+(2ab^2)^6+(8a^3b^5)^2=64a^6b^{12}+64a^6b^{12}+64a^6b^{10}=\\=128a^6b^{12}+64a^6b^{10}$

$2); ; (ax^2+bx+c)+(dx^2+nx+m)=-2x+6; ; Rightarrow \\(a+d)x^2+(b+n)x+(c+m)=0cdot x^2-2x+6; ; Rightarrow \\a+d=0; ,; b+n=-2; ,; ; c+m=6\\\(ax^2+bx+c)-(dx^2+nx+m)=4x^2; ; Rightarrow \\(a-d)x^2+(b-n)x+(c-m)=4x^2+0cdot x+0; ; Rightarrow \\a-d=4; ; ,; ; b-n=0; ,; ; c-m=0\\left { {{a+d=0} atop {a-d=4}} right.; ; left { {{d=-a} atop {2a=4}} righ; left { {{d=-2} atop {a=2}} right.$

$left { {{b+n=-2} atop {b-n=0}} right.; left { {{2n=-2} atop {2b=-2}} right.; left { {{n=-1} atop {b=-1}} right.\\left { {{c+m=6} atop {c-m=0}} right.; left { {{2c=6} atop {2m=6}} right. left { {{c=3} atop {m=3}} right.\\(2x^2-x+3)+(-2x^2-x+3)=-2x+6\\(2x^2-x+3)-(-2x^2-x+3)=4x^2$

$3); ; ax^{k}cdot bx^{m}cdot cx^{n}=65x^4; ; Rightarrow ; ; ; acdot bcdot c=65; ; ,; ; k+n+m=4\\65=1cdot 5cdot 13; ; ,; ; ; 1+1+2=4\\x^2cdot 5xcdot 13x=65x^4\\5x^2cdot xcdot 13x=65x^4\\5x^2cdot 13xcdot x=65x^4\\x^2cdot 13xcdot 5x=65x^4\\65x^2cdot xcdot x=65x^4\\x^2cdot ; 65xcdot x=65x^4\\x^2cdot xcdot ; 65x=65x^4$

$65x^2+x+x=65x^2+2x\\x^2+65x+x=x^2+66x\\x^2+x+65x=x^2+66x\\x^2+5x+13x=x^2+18x\\5x^2+x+13x=5x^2+14x\\5x^2+13x+x=5x^2+14x\\x^2+13x+5x=x^2+18x$