Question

помогите пожалуйста с и) к) л) м) (дам 100 балов)

Answer 1

и)

$frac{1}{2}(x-4) + 3x = 5\\x-4 + 6x = 10\\x+6x = 10+4\\7x = 14\\ x =2$

к)

$2(x+frac{3}{5}) - x = 3frac{1}{5}\\2x + 1frac{1}{5} - x = 3frac{1}{5}\\2x - x = 3frac{1}{5}-1frac{1}{5}\\x = 2$

л)

$5x - (frac{1}{2}x + 9) = 18\\5x - frac{1}{2}x - 9 = 18\\5x - frac{1}{2}x = 18 +9\\4frac{1}{2}x = 27\\x = 6$

м)

$-2(frac{1}{3}x + 7) = -21\\-frac{2}{3}x - 14 = -21\\-frac{2}{3}x = -21+14\\-frac{2}{3}x = -7\\frac{2}{3}x = 7\\x = frac{7*3}{2} = frac{21}{2}\\x = 10frac{1}{2}$