Question

4(3y+1)^2-27=(4y+9)(4y-9)+2(5y+2)(2y-7)

Answer 1

$36y^{2} +24y+4-27=16y^{2} -81+20y^{2} -70y+8y-28\36y^{2} +24y-23=36y^{2}-109-62y\24y-23=-109-62y\24y-23+109+62y=0\y+1=0\y=-1$