Question

Решите уравнение:
(2y – 3)(3y + 1) + 2(у – 5)(у + 5) = 2(1 - 2y)^2 + бу.

Answer 1

(2y-3)(3y+1)+2(y-5)(y+5)=2(1-2y)²+6y
6y²-9y+2y-3 + 2y² - 50 = 2 - 8y + 8y² + 6y
-7y + 2y = 2 + 3 + 50
5y = - 55
y = -11

Answer 2

$displaystyle tt (2y-3)(3y+1)+2(y-5)(y+5)=2(1-2y)^{2}+6y\\6y^{2}-9y+2y-3+2y^{2}-50=2-8y+8y^{2}+6y\\-7y+8y-6y=55\\-5y=55\\y=-11$