Question

AD=16 DC=25 Знайти AC,BD,AB​

Answer 1

BD^2=AD*DC DC=AD+7
144=AD*(AD+7) AD-x
144=x^2+7x
X^2+7x-144=0
D=49+144*4=625
x=(-7+-25)/2
X=9x=-16
AD=9 DC=16 AC=9+16=25
BC^2=625-400=225 AB=15 P=15+20+25=60