Question

f(x)=4/x - 1/4x^2+1/x^3+3​

Answer 1

f(x)=1/4.x^4+1/3.x^3+4.
f’(x)=4.1/4x^3+1/3.3.x^2=x^3+x^2
f’(x)=0,x^3+x^2=0,x^2(x+1)=0
x1=0,x2=0,x3=-1