Question

Просто разложить на множитили​

Answer 1

$sqrt2-2=sqrt2, (1-sqrt2)\\sqrt{10}-sqrt6=sqrt{2}, (sqrt5-sqrt3)\\a-2sqrt{a}=sqrt{a}, (sqrt{a}-2)\\a^2-3=(sqrt{a}-sqrt3)(sqrt{a}+sqrt3)\\m-100=(sqrt{m}-10)(sqrt{m}+10)\\1-2sqrt{p}+p=(1-sqrt{p})^2\\c+2sqrt{cd}+d=(sqrt{c}+sqrt{d})^2$