Question

1/2 log7(49m), если log7(m)=2 ​

Answer 1

$sf dfrac{1}{2}log_7(49m)=dfrac{1}{2}Big(log_749+log_7mBig)=dfrac{1}{2}Big(log_77^2+log_7mBig)=\ \ \ =dfrac{1}{2}Big(2+log_7mBig)=dfrac{1}{2}cdotBig(2+2Big)=2$