Question

tg (вквадрате) 6x-3=o

Answer 1

Ответ:

$tan {}^{2} (6x - 3) = 0 \ tan(6x - 3) = 0 \ 6x - 3 = arctan(0) + pi times n \6x = 3 + pi times n \ x = frac{1}{2} + frac{pi times n}{6}$

n є Z(целым числам)