Question

(3x+2)^2-x<=3x+56
Помоги пожалуйста

Answer 1

Ответ:

$x_1 = - 2 frac{8}{9} \ x_2 = 2$

Объяснение:

${(3x + 2)}^{2} - x = 3x + 56 \ 9 {x}^{2} + 12x + 4 - x = 3x + 56 \ 9 {x}^{2} + 11x + 4 = 3x+ 56 \ 9 {x}^{2} + 11x + 4 - 3x - 56 = 0 \ 9 {x}^{2} + 8x - 52 = 0 \ 9 {x}^{2} + 26x - 18x - 52 = 0 \ x(9x + 26) - 2(9x + 26) = 0 \ (9x + 26)(x - 2) = 0 \ 9x + 26 = 0 \ 9x = 26 \ x = - frac{26}{9} \ x_1 = - 2 frac{8}{9} \ x - 2 = 0 \ x_2 = 2$