Question

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Пожалуйста

Answer 1

$g'(x)=frac{6x}{pi } -2*frac{1}{cos^2x}\ \g'(frac{pi }{3})=frac{6}{pi } *frac{pi }{3}-2*frac{1}{0.5^2}=2-2*4=2-8=-6$

Answer 2

$g(x)=frac{3x^{2}}{pi }-2tgx-pi\\g'(x)=frac{3}{pi}*(x^{2})'-2(tgx)'-pi' =frac{6}{pi} x-frac{2}{Cos^{2}x}\\g'(frac{pi }{3})=frac{6}{pi }*frac{pi }{3}-frac{2}{Cos^{2}frac{pi }{3}}=2-frac{2}{(frac{1}{2})^{2}}=2-8=-6$