Question

$(x-2)^{2}=(x+3)(x-4)$

Answer 1

$(x-2)^2=(x+3)(x-4)\x^2-2cdot xcdot 2+4=x^2-4x+3x-12\x^2-4x+4=x^2-x-12\x^2-x^2-4x+x=-12-4\-3x=-16\x=frac{-16}{-3}\x=5frac{1}{3}$