Question

Освободиться от иррациональности в знаменателе дроби

Answer 1

$frac{22}{sqrt{13}-sqrt{2}}=frac{22}{sqrt{13}-sqrt{2}}cdot frac{sqrt{13}+sqrt{2}}{sqrt{13}+sqrt{2}}=frac{22(sqrt{13}+sqrt{2})}{(sqrt{13}-sqrt{2})(sqrt{13}+sqrt{2})}=frac{22(sqrt{13}+sqrt{2})}{11}=2(sqrt{13}+sqrt{2})=2sqrt{13}+2sqrt{2}$