Question

помогите пожалуйста решить

Answer 1

1.

a)mx+3m=m(x+3)

б)3ac-9bc=a·3c-3b·3c=3c·(a-3b)

в)a·(u-v)+b·(u-v)=(u-v)·(a+b)

г)b(2a+3c)-(2a+3c)=b·(2a+3c)-1·(2a+3c)=(2a+3c)·(b-1)

2.

a)...=(b-y)·(3+c)

б) ...=(a+2b)·(a-10)

в)...=(x-y)·(x²-1)

г)...=a·(c+n)+3k·(c+n)=(c+n)·(a+3k)

д)...=3y·(x-z)-5a··(x-z)=(x-z)·(3y-5a)

е)...=(x²y-a²x)+(y²x-a²y)=x·(xy-a²)+y·(xy-a²)=(xy-a²)·(x+y)

или

...=(x²y+y²x)-(a²x+a²y)=xy·(x+y)-a²·(x+y)=(x+y)·(xy-a²)

ж)...=(b³+b)+(7+7b²)=b·(b²+1)+7·(b²+1)=(b²+1)·(b+7)

или

...=(b³+7b²)+(7+b)=b²·(7+b)+(7+b)=(7+b)·(b²+7)

з)...=(10ax+10ay)+(5bx+5by)-(5x+5y)=10a·(x+y)+5b·(x+y)-5·(x+y)=

=(x+y)·(10a+5b-5)=5·(x+y)·(2a+b-1)