Question

Решите неравенст
1) 4х + 1 < 7;​

Answer 1

$displaystyle tt 4x+1<7\4x<7-1\4x<6\x<frac{6}{4}\x<frac{3}{2}\x<1,5$

Answer 2

4x < 1+ 7

4x< 7-2

4x<6

x < 6/4

x< 3/2

x< 1,5