Question

64х^3-16x^2 + x = 0​

Answer 1

Ответ:

1/8; 0

Объяснение:

$64 {x}^{3} - 16 {x}^{2} + x = 0 \ x(64 {x}^{2} - 16x + 1) = 0 \ x(8x - 1) {}^{2} = 0 \ x = 0 \ 8x - 1 = 0 \ x = frac{1}{8}$

Answer 2

$displaystyle tt 64x^3-16x^2+x=0\displaystyle tt x(64x^2-16x+1)=0\displaystyle tt x(8x-1)^2=0\displaystyle tt x_1=0\displaystyle tt 8x-1=0\displaystyle tt 8x=1\displaystyle tt x=frac{1}{8}\displaystyle tt x_2=0,125$