Question

Найдите корень уравнения 28(1-4x) = 7(3x+5).​

Answer 1

$displaystyle tt 28(1-4x)=7(3x+5)\ displaystyle tt 28-112x=21x+35\ displaystyle tt -112x-21x=35-28\ displaystyle tt -133x=7\ displaystyle tt x=frac{7}{-137}\ displaystyle tt x=-frac{1}{19}$

Answer 2

28(1 - 4 х) = 7(3 х + 5)
28 - 112 х = 21 х + 35
-112 х - 21 х = 35 - 28
-133 х = 7
1
х = - —
19