Question

3 1/6 +(-2 5/6)+1 7/12
решить удобым способом

Answer 1

$displaystyle tt 3frac{1}{6}+(-2frac{5}{6})+1frac{7}{12}=frac{19}{6}-frac{17}{6}+frac{19}{12}=frac{2}{6}+frac{17}{12}=frac{4}{12}+frac{19}{12}=frac{23}{12}=1frac{11}{12}$

Answer 2

$3dfrac16+bigg(-2dfrac 56bigg)+1dfrac 7{12}=3dfrac16^{(2}+1dfrac 7{12}+bigg(-2dfrac 56bigg)=\\\=3dfrac2{12}+1dfrac 7{12}-2dfrac 56^{(2}=4dfrac 9{12}-2dfrac {10}{12}=3dfrac{21}{12}-2dfrac {10}{12}=\\\boldsymbol{=1dfrac {11}{12}}$