Question

x-3/x-2+x-7/2-x=20/x2-4

Answer 1

На фотографии подробно.

Answer 2

$displaystyle tt frac{x-3}{x-2}+frac{x-7}{2-x}=frac{20}{x^2-4}: : : : | : xne2, : xne-2\displaystyle tt frac{x-3}{x-2}+frac{x-7}{2-x}-frac{20}{x^2-4}=0\displaystyle tt frac{x-3}{x-2}+frac{x-7}{-(x-2)}-frac{20}{(x-2)(x+2)}=0\displaystyle tt frac{x-3}{x-2}-frac{x-7}{x-2}-frac{20}{(x-2)(x+2)}=0\displaystyle tt frac{(x+2)(x-3)-(x+2)(x-7)-20}{(x-2)(x+2)}=0\displaystyle tt frac{x^2-3x+2x-6-(x^2-7x+2x-14)-20}{(x-2)(x+2)}=0$

$displaystyle tt frac{x^2-3x+2x-6-(x^2-5x-14)-20}{(x-2)(x+2)}=0\displaystyle tt frac{x^2-3x+2x-6-x^2+5x+14-20}{(x-2)(x+2)}=0\displaystyle tt frac{4x-12}{(x-2)(x+2)}=0\displaystyle tt 4x-12=0\displaystyle tt 4x=12\displaystyle tt x=frac{12}{4}\displaystyle tt boxed{bold{x=3}}$