Question

(х-2)(х-3)-(х+1)(х-4) = 0 решить уравнение

Answer 1

$(x { }^{2} - 3x - 2x + 6) - (x {}^{2} - 4x + x - 4) = 0 \ x {}^{2} - 3x - 2x + 6 - x {}^{2} + 4x - x + 4 = 0 \ - 2x + 10 = 0 \ - 2x = - 10 \ x = 5$