Question

(3х + 4)^2 - (3x - 1)(3x + 1) = 41. Решите пожалуйста!

Answer 1

$(3x+4)^2-(3x-1)(3x+1)=41\9x^2+24x+16-(9x^2-1) = 41\9x^2+24x+16-9x^2+1 = 41\24x+17=41\24x=41-17\24x=24\x=1$

Answer 2

$(3x+4)^2-(3x-1)(3x+1)=41\\9x^2+24x+16-(9x^2-1)=41\\24x+17=41\\24x=24\\x=1$