Question

РЕШИТЕ УРАВНЕНИЕ!!!!

Answer 1

${y}^{3} + {7y}^{2} + 12y = 0 \ y( {y}^{2} + 7y times 12) = 0 \ y( {y}^{2} + 4y + 3y + 12) = 0 \ \ y(y (y + 4) + 3(y + 4)) = 0 \ y(y + 4)(y + 3) = 0 </strong></p><p><strong> \ y</strong><strong>1</strong><strong> = - 4 \ y</strong><strong>2</strong><strong> = - 3$