Question

Розклади на множники вирази: 1+6х+9х^2; 36у^2+12у+1; -4с^2-4c-1;

Answer 1

$displaystyle tt 1+6x+9x^2=1^2+2cdot1cdot3x+3^2x^2=1^2+2cdot1cdot3x+(3x)^2=(1+3x)^2=bold{(1+3x)(1+3x)}$

$displaystyle tt 36y^2+12y+1=6^2y^2+2cdot6cdot1+1^2=(6y)^2+2cdot6ycdot1+1^2=(6y+1)^2=bold{(6y+1)(6y+1)}$

$displaystyle tt -4c^2-4c-1=-4c^2-2c-2c-1=-2c(2c+1)-(2c+1)=bold{-(2c+1)(2c+1)}$